Solve for x: −5|x + 1| = 10

x = 0

x = −3 and x = 1

x = −1 and x = 3

No solution

Question

Solve for x: −5|x + 1| = 10

 x = 0

 x = −3 and x = 1

 x = −1 and x = 3

 No solution

owlcoffee · Answer

$$-5(x+1)=10$$
let's apply distributive:
$$-5x-5=10$$
if we add 5 to both sides we get:
$$-5x=15$$
You can take over from here on :)

anonymous · Answer

@Owlcoffee the brackets are absolute brackets

austinl · Answer

That would only be one answer. You would need to solve for the other answer. However, because this is multiple choice it narrows down the correct answer.

owlcoffee · Answer

oh my. then we'll have to evaluate that absolute value, making the opposite of that~

anonymous · Answer

So B??

anonymous · Answer

how do you make the opposite of it ?

anonymous · Answer

−5|x + 1| = 10

first step?

anonymous · Answer

divide -5 ?

anonymous · Answer

| x + 1| = -2

owlcoffee · Answer

When we solve for an abs. value, we get two ecuations:

1) $$-5(x+1)=10$$
2)$$-5(-\left[ x+1 \right])=10$$
Solve for x on those two and you'll get the answer.

anonymous · Answer

thanks

austinl · Answer

$−5|x + 1| = 10$

Divide by -5.
$|x+1|=-2$

That means that we have,
$x+1=-2$
&
$-(x+1)=-2$
$-x-1=-2$

Solve each of them,
$x=-3$
$x=1$

Now this is what I get, however wolfram alpha says no solutions.

anonymous · Answer

the issue is that the absolute brackets makes everything positive
when the other side of the equation has a negative sign

I guess thats why theres no solution - the sign on the LHS and RHS
always conflict