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Use the reduction formula for cosine to find the integral of cos(8x)^2dx and cos(8x)^4dx.
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cos^2x = (1+cos2x)/2. So the first one just becomes (1+cos16x)/2, which you can reduce from there. For the second one you're forced to do it twice. Its the same deal, just requires more algebra and care.
Would you know how to go about integrating the first one after (1+cos16x)/2?
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