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Mathematics 18 Online
OpenStudy (anonymous):

Trevor is tiling his bathroom floor, which has an area that is represented as 117r4 square inches. Each tile has an area of square root of the quantity 9 r to the thirteenth power . The total number of tiles used can be represented by the expression below. one hundred seventeen r to the fourth power, all over the square root of the quantity nine r to the thirteenth power Simplify the expression for the total number of tiles used. Show your work. @blurbendy blur is it ok if you do it for me i do not understand nothing that the question is asking

OpenStudy (blurbendy):

Basically, it wants you to simplify (117r^4) / sqrt(9r^13)

OpenStudy (anonymous):

ok let me do that and you tell me if i got it right ok>

OpenStudy (blurbendy):

sure

OpenStudy (anonymous):

is it 13/sqrtr^9 or s it 13/r^9?

OpenStudy (blurbendy):

does this one have answer choices?

OpenStudy (anonymous):

no it does not it's an essay question

OpenStudy (blurbendy):

okay, I got ( 39sqrt[r^13] ) / r^9

OpenStudy (anonymous):

ok can you show me how?

OpenStudy (blurbendy):

(117r^4) / sqrt(9r^13) if that's what we start with, then let's look at the bottom part first. the square root of 9 is 3, so now we have (117r^4) / 3sqrt[r^13] 117/3 = 39, so now we have 39r^4 / sqrt[13] square roots in the denominator are bad, so we'll multiply the top and bottom by the sqrt[r^13] now we have r^4sqrt[13] / r^13 (notice that the square root on the bottom went to the top when we multiplied both sides by the sqrt[13] we can simplify 39r^4sqrt[13] / r^13 to 39sqrt[13] / r^9 (we just subtracted r^4 from r^13 to get r^9 on the bottom

OpenStudy (anonymous):

ok now what?

OpenStudy (blurbendy):

the bottom expression is your answer

OpenStudy (anonymous):

so is that all?

OpenStudy (blurbendy):

39sqrt[13] / r^9 tiles were used

OpenStudy (anonymous):

thank you so much

OpenStudy (blurbendy):

anytime

OpenStudy (anonymous):

good night

OpenStudy (blurbendy):

see you

OpenStudy (anonymous):

wait one quick question shouldn't it be 39r^4sqrt^13? instead of 39r^4sqrt13

OpenStudy (anonymous):

@blurbendy

OpenStudy (blurbendy):

?

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