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Find the equation perpendicular to 2y-4x=8 and passes the point (8,2) . Can someone explain how to do it please? -Geometry
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Change the given equation to slope intercept form, y=mx+b That will help you determine the slope of the given line
What did you get
2y=4x+b ?
close 2y = 4x + 8 No divide everything by 2 so you get y= mx+b
Now
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did u get y=2x+4
yes
You'll see that the slope of the given line is 2. To have a perpendicular line, the slope is the opposite reciprocal.....-1/2
Using the slope intercept formula and the point given (8,2) plug in and find b.
2=-1/2(8)+b
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Are you still there
2=-4+b 6=b Now you can give the equation of a line perpendicular to the given line at the point (8,2). y=-1/2x+6
oh i see
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