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∠ RQS and ∠ TQP are vertical angles where m∠ RQS = 3(x + 7) and m∠ TQP = 4x + 15. 1. Solve for x. 2. Find m∠ RQS and m∠ TQP 3. Show how you can check your answer.
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Do I start this by combining like terms?
∠ RQS and ∠ TQP are vertical angles so this means that the two angles are congruent
so... m∠ RQS = m∠ TQP 3(x + 7) = 4x + 15 x = ???
3x + 21 = 4x + 15
keep going
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3x + 21 = 4x + 15 - 21 -21 = 3x = 4x - 6
3x/3 = 4x/3 - 6 x = -6
very good
actually sorry
it should be -x = -6 so x = 6
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you were close though
oh okay well then I plug that into the equations right?
yes into each angle equation
Thanks :)
sure thing
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