i neeed helpppppp
What's the question?
^
i need to change this linear equation to standard form 10y-3x+6=11
Standard form is Ax+By=C A, B, C are all integers, GCF of 1, and A is positive. So, get all the x's and y's on one side, leave all the numbers on the other.
howww
You already have the x's and y's on one side, so get all the numbers on the other, by subtracting 6 on both sides
ok i have 10y-3+6=5
3x*
That's not correct, only the right side is. Subtract 6 on BOTH sides of: 10y-3x+6=11
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That's good. THen do you see the mistake you made in this... 10y-3+6=5
okokokokok 10y-3x=5 not what
now*
Good. Now, change the order so the x comes first 10y - 3x = 5 becomes -3x + 10y = 5 Now one more step... the number in front of x needs to be positive.
10y-3x+6=11 10y - 3x = 5 -3x +10y = 5 3x + 10y = -5
soo i just move it over?????
to make the x positive? no. Multiply both sides by -1.
oh my bad, 3x - 10y = -5
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