A box contains one yellow, two red, and three green balls. Two balls are randomly chosen without replacement. Define the following events:
A: \{ One of the balls is yellow \}
B: \{ At least one ball is red \}
C: \{ Both balls are green \}
D: \{ Both balls are of the same color \}

Find the following conditional probabilities:
(b) P(D|B) =

Question

A box contains one yellow, two red, and three green balls. Two balls are randomly chosen without replacement. Define the following events:
A: \{ One of the balls is yellow \} 
B: \{ At least one ball is red \} 
C: \{ Both balls are green \} 
D: \{ Both balls are of the same color \}

Find the following conditional probabilities:
(b)  P(D|B) =

anonymous · Answer

I understand that at least one has to be red, and they both have to be the same color, so you can only have both red balls, but when trying to compute the probability, I'm not sure whether to use a combination or use Baye's Rule.