Question

How do i find the derivative of y=e^(lnx^2)-3x^(-7)
I know the second part is 21x^(-8) i just dont understand the first part

Answer 1

does it help to know that
\[e^{\ln(whatever)}=whatever\]?

Answer 2

to be clear the exact equation is\[y=e^{\ln x ^{2}}-3x ^{-7}\]

Answer 3

then it is
\[x^2-3x^{-7}\] take the derivative of that one

Answer 4

i got 2x+21/(x^8)

Answer 5

me too

Answer 6

heck yeah thanks