HELP : Part (ii) (b) (i) Express (√6) cos θ + (√10) sin θ in the form R cos(θ − α ), where R > 0 and 0◦< α < 90◦. Give the value of α correct to 2 decimal places. (ii) Hence, in each of the following cases, find the smallest positive angle θ which satisfies the equation (a) (√6) cos θ + (√10) sin θ = −4, (b) (√6) cos1/2θ + (√10) sin1/2θ = 3
@hartnn @thomaster
do you know the expansion of cos(theta-alpha) ?
i just need help for ( ii) part (b)
is it theta/2 or 1/(2theta)
\[4 \cos \left( \theta/2 - \alpha \right) = 3\] \[\alpha = 53.238..\]
\[\left( \theta/2 - \alpha \right) = \cos^{-1} \frac{ 3 }{ 4 }\]
yeah you are right.............now substitute the values
theta / 2 = cos inverse 3/4 + alpha... theta = 2 ( cos inverse 3/4 + alpha) = 189.2952
but thats not the right answer :S
let me check a moment
@satellite73
k i got it
theta - alpha/2 can be negative also
its just : theta /2 not alpha...
sry.......theta/2 - alpha can be negative also....................you know cos ^-1(3/4) is also -41.4
try this value you will get your answer.........i expect the answer is 23.6
yep but the answer should be : 21.7 ~_~
(Y) ! :D
but one more question : how do we know when to take negative for cos-1 ?
why take negative of cos inverse rather than positive o.o ?
in this case you should check with both to see which one is giving you the smallest angle.........because the question says find smallest positive angle
suppose the question was to find all values of theta then i should take cos both positive and neg ?
yup.......and if the question is to find ALL the values of theta, then there are several answers.....remember trigonometric functions start repeating again and again
:D ty :D !
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