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Use the discriminant to find the number of real solutions of the following quadratic equation: 2x2 + 2x + 2 = 0. A. no real solutions B. 1 real solution C. 2 real solutions D. 3 real solutions
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2(x^2+x+1)
=0
so one solution?
2(x+1)^2=0
Divide both sides with 2.
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(x+1)^2=0
x+1=0
x=-1
i have no clue what you are trying to do. it askes for solutions not evaluate
It IS the solution.
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THE solution.
since its -1 that means no real solution
It is real and negative.
so ONE solution?
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I think yes. If you want to be sure goe on this webpage http://www.wolframalpha.com/
It helps a lot when you need help for equations.
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