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how do i solve this? (transforming formulas algebra 1) please show me step by step it would help alot thanks 10ac-x/11=-3 solve for a
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is it all over 11 like \[\frac{10ac-x}{11}=-3\]
or is just the \(x\) over 11 like \[10ac-\frac{x}{11}=-3\]?
first one
step one: multiply both sides by \(11\) to get rid of annoying fraction you get \[10ac-x=-33\]
step 2: add \(x\) to both sides and get \[10ac=-33+x\] or if you prefer \[10ac=x-33\]
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and since you are solving for \(a\) the last step is to divide both sides by \(10c\) to get \[a=\frac{x-33}{10c}\] then it is done
that was step by step as requested, hope it is okay
thank you so much, it was very helpful!
yw
|dw:1380245346534:dw| what about this one?
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