Question

Given that f(x) = 3x + 1 and g(x) = the quantity of 4x plus 2 divided by 3 solve for g(f(0)).

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Answer 1

f(x) = 3x + 1


g(x) = \[4x + 2 \over 3\]

Answer 2

@ganeshie8

Answer 3

g(f(0))
^^

Answer 4

first find f(0)

Answer 5

sorry was afk eating lunch

Answer 6

f(x) = 3x + 1
F(0) = 3(0) + 1

0 = 0 + 1
0 = 0?

Answer 7

f(x) = 3x + 1
F(0) = 3(0) + 1
= 0 + 1
= 1

Answer 8

f(0) = 1

Answer 9

plug that in g(f(0))

g(1)

Answer 10

g(1)..

Answer 11

yup, find it

Answer 12

4x + 2 / 3

4(1) + 2 / 3

4 + 2 = 6

6/3

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Answer 13

Yes !!

Answer 14

good job :)

Answer 15

thanks man :D