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What is the solution to the equation 1 over the square root of 8 = 4(m + 3)
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\[\frac{ 1 }{ \sqrt{8} } = 4(m+3)\]
is that correct?
m = –15 over 4 m = –11 over 4 m = 5 over 4 m = 9 over 4
4m+12 = \(\frac{1}{\sqrt{8}}\), subtract by 12, and then divide by 4.
by the way, \(\sf \color{red}{\sqrt{8}=2\sqrt{2}}\)
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You might want to reduce that, it helps.
thanks
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