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Mathematics 19 Online
OpenStudy (anonymous):

a bag contains 5 blue balls, 3 white balls, 2 red balls. if we peak 6 balls randomly what is probability to peak 3 blue 2 white and 1 red?

OpenStudy (praxer):

The probability of an event = know of events/ favorable outcome can you proceed now, @syltan

OpenStudy (anonymous):

well i know that. but is this a counting problem? because i dont know how to start it.

OpenStudy (praxer):

show me how, you have proceeded

OpenStudy (anonymous):

i think for number of event we have to search no of combinations using formula nCr ie 5C3 * 3C2 * 2c1 is it @praxer

OpenStudy (anonymous):

we peak numerator( 3 out of 5)(2 out of 3) (1 out of 2) denominator(6 out of 10)

OpenStudy (anonymous):

is it like this i am not sure.

OpenStudy (anonymous):

@syltan : it will be like that little bit more it can be any combination of 6 ball out to 10 ball in denominator and in numerator ie know of events it will be 5C3 * 3C2 * 2c1 here * (multiply ) bcoz all three even are happening at same time so answer wil be (5C3 * 3C2 * 2c1 )/10C6

OpenStudy (08surya):

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