You're driving down the highway late one night at 18m/s when a deer steps onto the road 39m in front of you. Your reaction time before stepping on the brakes is 0.50s , and the maximum deceleration of your car is 12m/s2 .
How much distance is between you and the deer

when you come to a stop?
=17m

What is the maximum speed you could have and still not hit the deer?
= ?

Question

You're driving down the highway late one night at 18m/s when a deer steps onto the road 39m in front of you. Your reaction time before stepping on the brakes is 0.50s , and the maximum deceleration of your car is 12m/s2 .
How much distance is between you and the deer 

when you come to a stop?
=17m

What is the maximum speed you could have and still not hit the deer?
= ?

anonymous · Answer

You have to find the maximum initial velocity here, when with a maximum deceleration of 12 m/s^2 you can stop the car just before the deer. Also, you found the distance, s=17 m.

So, enter all the value into the very common eqn of kinematics-

v^2=u^2-2*a*s              u=initial velocity       v=0=final velocity

anonymous · Answer

Wait, I made a mistake, Let me think a while.

anonymous · Answer

I think you made a wrong calculation. The first answer should be= 16.5 m

anonymous · Answer

Try s=30 m in the above eqn. Because the brak

anonymous · Answer

*Because the brake was being applied during this time.

loser66 · Answer

@idban , he is right, he takes significant figure (2 sg.f)

loser66 · Answer

attachment