Question

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Answer 1

a = 1
b = 4
c = 2

\[x = (-b \pm \sqrt{b^2-4ac})/2a\]

So plug in a, b, and c.

\[x = (-4 \pm \sqrt{4^2-8})/2\]
\[x = (-4 \pm \sqrt{16-8})/2\]
\[x = (-4 \pm \sqrt{8})/2\]

Answer 2

For +

\[x = (-4 + \sqrt{4 \times 2})/ 2\]
\[x = (-4 + 2\sqrt{2})/2\]
\[x= -2 +\sqrt{2}\]

For -
\[x = (-4 - \sqrt{4 \times 2})/ 2\]
\[x = (-4 - 2\sqrt{2})/2\]
\[x= -2 -\sqrt{2}\]

Answer 3

So your answer is
\[x = -2 \pm \sqrt{2}\]