Question

Find the equation of a line that meets the given condition : perpendicular to 6x-2y=10,passes through (6,-3)

Answer 1

first thing we have to do is find the slope of the given equation. Do you know how to do that ?

Answer 2

No

Answer 3

put the equation , 6x - 2y - 10, into y = mx + b form.
Can you do that ?

Answer 4

oops...6x - 2y = 10

Answer 5

slope = -a/b

Answer 6

put your equation in y = mx + b form to find the slope

Answer 7

do you need help in doing this ?

Answer 8

slope is -6/-2
=3

Answer 9

so the slope of the line perpendicular to it is -1/3

Answer 10

the asker needs to learn how to find the slope

Answer 11

I want you to tell me how to find slope explain the steps then I can learn

Answer 12

how to put your equation in y = mx + b form...
6x - 2y = 10 (subtract 6x from both sides)
-2y = -6x + 10 (now divide by -2)
y = -6/-2y + 10/-2
y = 3/1x - 5

your slope in y = mx + b form is in the position of m.
therefore, your slope in this equation is 3/1.

Do you understand so far ?

Answer 13

typo...y = -6/-2x + 10/-2

Answer 14

Yes I do thanks

Answer 15

now we are looking for a perpendicular line, therefore we need to find the negative reciprocal of the slope 3/1. To find the negative reciprocal , we " flip " the fraction and change the sign.
Therefore, the perpendicular slope we need is -1/3.

Understand so far ?

Answer 16

@shakur ...you still with me ?

Answer 17

Yes I was trying to work on similar equation using the steps you gave me

Answer 18

now we need to find the equation of the perpendicular line. To do this we will use this formula : y - y1 = m(x - x1)
slope(m) = -1/3
(6,-3) x1 = 6 and y1 = -3

now lets sub
y - (-3) = -1/3(x - 6)
y + 3 = -1/3x + 2
y = -1/3x + 2 - 3
y = -1/3x - 1 <-- your equation

do you understand ? do you have any questions ? I will be more then happy to answer them.

Answer 19

I am fine,I will solved it now and let you if i got it accoring to your steps

Answer 20

Just remember, when you are looking for a perpendicular line, you need the negative reciprocal of the slope given. Now if you were looking for a parallel line, the slope would be the same as the slope given.