Can somebody please help me with my question?
Here is the question.
Do you know how to make graph for normal line equations?
No I never relly understood that stuff.
Take a point in one of the regions ((0,0) is an easy one) and test it in the inequality. If it's true, then that is the solution region. If it's false, then the other part of the plane is the solution region.
The only other difference is the solid vs. the dashed line. Dashed is for a strict inequality (<, >) and solid means that the points ON the line are also part of the solution set, so for a weak inequality (\(\le, \ge\))
But, as @Aditi_Singh indicates, before you can really understand the graph of a linear inequality, you should have a firm grasp of the concepts related to the graph of a line (a linear EQUality). The linear equation associated with the inequality is what gives you the line that is the border between the solution and non-solution regions of the plane.
Isn't it d?
fine. Let us take the example of the given line itself.. 3y-5x=-6 |dw:1380570547310:dw| => when x =0, y=-2, and when y =0 , x=1.2
now start making the graph .. |dw:1380570749971:dw|
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