Limit, When it says to show for any integer n what does it mean ? http://screencast.com/t/VQyTJhdwg
like how can I "show " ?
usually by induction... have you learned L'Hopital's rule? Have you learned about series?
l hopital yes , series no , I am basically learning alone
use can use L'Hopital's... the first: \[\lim_{x \rightarrow +\infty}\frac{ \ln x }{ x^n }\overset{H}{=}\lim_{x \rightarrow +\infty}\frac{ \frac{ 1 }{ x } }{ n\cdot x^{n-1} }=\lim_{x \rightarrow +\infty}\frac{ 1 }{ n\cdot x^{n} } = 0\text{, }\forall n \in \mathbb{Z}^+\]
do the same for the other... no induction needed.
ps. it's for any positive integer n, not any integer.
do you know what this says?
i mean, what the limit says?
b) results in inf/0 , is that allowed or am I doing something wrong ? Wolfram says that inf/0 is "complex infinity" ... isn't that undefined ?
no, you should get infinity/1
:o
how did you do it ? can you show me please ?
look at what i did previously and just flip it. remember, when you get 1/x to move the x to the appropriate place (numerator or denominator) and don't leave it as 1/x.
you should get \[\lim_{x \rightarrow +\infty}\frac{ n\cdot x^{n} }{ 1 }\]
look. it gives me inf * inf
x n x^(n-1) = n x^n when put x = infinity nx^n = infinity
really? you're not so comfortable moving things around and you should be at this level!\[\lim_{x \rightarrow +\infty}\frac{ x^n }{ \ln x }\overset{H}{=}\lim_{x \rightarrow +\infty}\frac{ n\cdot x^{n-1} }{ \frac{ 1 }{ x } }=\lim_{x \rightarrow +\infty}\frac {n\cdot x^{n-1} }{ 1} \cdot \frac{ x }{ 1 } =\lim_{x \rightarrow +\infty}\frac {n\cdot x^{n} }{ 1} = +\infty \text{, }\forall n \in \mathbb{Z}^+\]
Oh I see , thanks
You are right bro, I should see this coming , proof that I need some practice !
thanks btw
it's okay... I've taught calc before and most students struggle with the algebra and trig. experience is a great teacher, too. so do your best to remember how to make something look different even though it's really the same. kind of like getting dressed up for halloween
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