Help asap plz ill give a gold medal. the label on cars antifreeze claims to protect the car between -30celsius and 130celsius. to convert Celsius temperature Fahrenheit temperature, the formula is, c=5/9(F-32). Write an solve and inequality to determine the Fahrenheit temperature range at which antifreeze protects the car.

Question

anonymous · Answer

you have C and you want F
use 
$$F=\frac{9}{5}C+32$$ to find it

anonymous · Answer

now you need to replace $C$ by $-30$ and get
$$F=\frac{9}{5}\times (-30)+32$$
$$F=-54+32=-22$$

anonymous · Answer

next step is to replace $C$  by $130$

anonymous · Answer

oh ok

anonymous · Answer

let me know what you get

anonymous · Answer

cant figure it out can you keep going

anonymous · Answer

can you help with this one mertsj

anonymous · Answer

first step is to write 
$$F=\frac{9}{5}\times 130+32$$

anonymous · Answer

then you have to compute 
$$\frac{9}{5}\times 130$$
how many times does $5$ go in to $130$ i.e. what is $130\div 5$?

anonymous · Answer

um 26

anonymous · Answer

ok good
now what is $9\times 26$?

anonymous · Answer

234

anonymous · Answer

right, so $\frac{9}{5}\times 130=234$ and finally what is $234+32$?

anonymous · Answer

266

anonymous · Answer

so it is
therefor the answer you are looking for is it protects cars from $-22$ to $226$ or you could even write 
$$-22\leq x\leq 226$$ if you like