You are going to fence an area that is in the shape of a right triangle. The two legs measure 7.8 m and 5.78 m. Estimate the meters of fencing you will need for the longest side, using whole meters and square root.
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OpenStudy (smileyxl3):
Since its a right triangle a^2 + b^2 = c^2
OpenStudy (anonymous):
Are you familiar with the Pythagorean theorem?
OpenStudy (anonymous):
^
OpenStudy (smileyxl3):
Lol great minds think alike
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
\[a^2+b^2=c^2 \] where a and b are shorter sides of the triangle, and c is the longest side.
OpenStudy (smileyxl3):
You have to round them up too. 7.8=8 and 5.78=6. that should be easier
OpenStudy (anonymous):
So for this we can represent this as \[(5.78)^2+(7.8)^2=c^2\]
OpenStudy (anonymous):
So\[c=\sqrt{(5.78)^2+(7.8)^2}\]
OpenStudy (anonymous):
right
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OpenStudy (smileyxl3):
\[6^2+8^2=c^2\]
OpenStudy (anonymous):
\[c \approx100m\]
OpenStudy (smileyxl3):
\[\sqrt{36+64}\]
OpenStudy (anonymous):
Oops...
OpenStudy (anonymous):
Forgot my square root!!
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OpenStudy (smileyxl3):
@escolas I think it would have been easier to calculate if you just rounded the sides first. and yea you forgot your square
OpenStudy (anonymous):
\[c \approx \sqrt{100}\]
OpenStudy (smileyxl3):
perimeter = 10 + 8 + 6 = 24. By the way, this is a 3 4 5 triangle ;)
OpenStudy (anonymous):
It would have been, but for real math it's much less accurate. I mean I wasn't sure it'd come out to 9 or 10, it did happen to be barely closer to 10 so it would round up.