Ask your own question, for FREE!
Algebra 8 Online
OpenStudy (anonymous):

cos2x/sin2x + sinx/cosx = csc2x

OpenStudy (akashdeepdeb):

Is that supposed to be cos2x or cos^2 x ?

OpenStudy (anonymous):

cos2x

OpenStudy (akashdeepdeb):

Okay so.. cos2x/sin2x = cot2x = 1/tan2x sinx/cosx = tan x Thus by adding them we get the LHS as 1/tan2x + tan x Understood till here?

OpenStudy (anonymous):

yes

OpenStudy (akashdeepdeb):

Okay do you know what tan2x is? Use Identity of tan(A+B) :D

OpenStudy (anonymous):

2tanx/1-tan^2(x) right?

OpenStudy (akashdeepdeb):

Awesome. Now we know tan2x to be 2tanx/(1-tan^2x) Thus 1/tan2x + tan x Equals (1-tan^2x)/2tanx + tanx YEAH? :D Now take LCM as 2tanx Then write tan in sin/cos form. And tell me what you get. :D

OpenStudy (anonymous):

ahhhh i see!! thank you so much! i was stuck on that second part

OpenStudy (akashdeepdeb):

Okay so I suppose you got it then. :)

OpenStudy (anonymous):

sure did! thank you!

OpenStudy (akashdeepdeb):

:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!