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Algebra
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cos2x/sin2x + sinx/cosx = csc2x
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Is that supposed to be cos2x or cos^2 x ?
cos2x
Okay so.. cos2x/sin2x = cot2x = 1/tan2x sinx/cosx = tan x Thus by adding them we get the LHS as 1/tan2x + tan x Understood till here?
yes
Okay do you know what tan2x is? Use Identity of tan(A+B) :D
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2tanx/1-tan^2(x) right?
Awesome. Now we know tan2x to be 2tanx/(1-tan^2x) Thus 1/tan2x + tan x Equals (1-tan^2x)/2tanx + tanx YEAH? :D Now take LCM as 2tanx Then write tan in sin/cos form. And tell me what you get. :D
ahhhh i see!! thank you so much! i was stuck on that second part
Okay so I suppose you got it then. :)
sure did! thank you!
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