1/7(14-7 p) - 2=-2(1/2p+3)+6 solve the equation step by step please
lets start with \[\frac{1}{7}\left(14-7p\right)\] what do you get when you multiply out using the distributive law?
2-1p ?
yes, good
now we have on the left \[2-p-2\] or just \(-p\)
on the right, start with \[-2\left(\frac{1}{2}p+3\right)\] and multiply what do you get for this one?
-1p-6?
yup. so far so good now what is \(-p-6+6\)?
-p-12?
not quite what is \(-6+6\) or if you prefer \(6-6\)?
0
right, so what is \(-p-6+6\)?
0?
well actually you are left with \(-p\)
so on the left we removed parentheses, combined like terms, and ended up with \(-p\) and on the right the same thing happened, we also ended up with \(-p\) now the equation looks like \[-p=-p\]
oh ok so thats the answer
the actual answer is "this is an identity" since \(-p=-p\) is always true in other words, both the left and right hand side of this equation are always the same, not matter what you put in for \(p\)
*no matter
Oh ok thank you very much (:
yw
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