Question

What is the simplified form of

Answer 1

of?

Answer 2

I'm going to post the problem

Answer 3

\[\frac{ 8x+3 }{ 12y^4 }\times \frac{ 20y^6 }{ 6x^8 }\]

Answer 4

multiply the top of both terms first, then divide the multiplication of the numerators. Does that make sense?

Answer 5

not at all.... Sorry, it's really late here and I'm so confused...

Answer 6

do it in parts can you simplify
\[ \frac{y^6}{y^4} \]

Answer 7

y^2?

Answer 8

yes. that means your problem
\[ \frac{ 8x+3 }{ 12y^4 }\cdot \frac{ 20y^6 }{ 6x^8 } \\
\frac{ 8x+3 }{ 12 }\cdot \frac{ 20y^2 }{ 6x^8 }
\]
now simplify
20/(12*6)

Answer 9

5/19?

Answer 10

I get 5/18

Answer 11

my bad, yeah it's 5/18

Answer 12

\[ \frac{ 8x+3 }{ 12 }\cdot \frac{ 20y^2 }{ 6x^8 } \\
\frac{ 8x+3 }{ 1 }\cdot \frac{ 5y^2 }{ 18x^8 }
\]
we can't do much more

Answer 13

can we do anything else? It's multiple choice and that's not one of the choices...

Answer 14

I was suspicious of this problem. can you post the exact question and choices ?

Answer 15

sure

Answer 16

oh. notice that the question has 8x^3 and you wrote 8x+3 which is *very* different

Answer 17

wow... that wasn't a very intelligent thing to do.... sorry

Answer 18

so what you have is
\[ \frac{ 8x^3 }{ 1 }\cdot \frac{ 5y^2 }{ 18x^8 } \]

now we can simplify the numbers: 8*5/18 simplifies to what ?


can you simplify
\[ \frac{x^3}{x^8} \]?

Answer 19

wow... that wasn't a very intelligent thing to do.... sorry

I would say sloppy... which is different... you can fix sloppy

Answer 20

1/x^5?

Answer 21

yes. remember that
\[\frac{x^3}{x^8} = \frac{x \cdot x \cdot x}{x \cdot x \cdot x \cdot x \cdot x \cdot x \cdot x \cdot x } = \frac{ \cancel{x \cdot x \cdot x}}{\cancel{x \cdot x \cdot x}\cdot x \cdot x \cdot x \cdot x \cdot x} \]

Answer 22

8*5/18 simplifies to what ?

I would divide top and bottom by 2 to get 4*5/9
which is 20/9

Answer 23

thank you soooooo much

Answer 24

\[ \frac{ 20y^2 }{ 9x^5 } \]