Question

Let f(x) = 3x^(4)+4x^(3)/7x+4. Evaluate f'(x) at x = 2 f'(2)=?
I have no idea how to even start this...please help

Answer 1

take the derivative and plug in 2 for x for the derivative to get the answer

Answer 2

Okay love, all you need to do is plug the x (2) into the original equation. So it's 3(2)^4+4(2)^3/7(2)+4

Answer 3

f'(x)=x^2(63x^2+104x+48)/(7x+4)^2

Answer 4

f'(2)=508/81

Answer 5

Hey Nickolena, do you remember how to apply the `Quotient Rule` ? :)

Answer 6

hey zepdrix can you help with my question?

Answer 7

what L00Pz says is wrong, just follow what I did. To take the derivative you can use quotient rule like zepdrix said. Then once you have the derivative sub in 2 for x and you will get the answer.

Answer 8

How's it wrong? It's just asking to evaluate a function with a given X?

Answer 9

See the little tick mark on the f loops? D:
That signifies the derivative function.

Answer 10

It says evaluate the derivative f prime of x not f(x)

Answer 11

Oh my, i didn't even see that. Thanks buddy!