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Mathematics 14 Online
OpenStudy (anonymous):

find θ-> sec θ = -1.0365

OpenStudy (homeworksucks):

First, take the literal inverse of the function, so 1/-1.0365, would give you cos (theta). Take the arccos of whatever the inverse of -1.0365, but make it positive. This gives you your reference angle. To find the actual angle, use the CAST(or ASTC) rule to find which two quadrants which cosine is negative. Then use the rules for finding the angle in each quadrant given the reference.

OpenStudy (anonymous):

im getting 2.8754

OpenStudy (homeworksucks):

Radians?

OpenStudy (anonymous):

im not sure.. i did 1/-1.0365 then i took that answer (-.96478) and i did cos-1 (-.964785) ad i got the 2.8754

OpenStudy (homeworksucks):

Oh, you want positive .964785

OpenStudy (homeworksucks):

Yeah, and you're in radians

OpenStudy (anonymous):

ok so now i got .26617

OpenStudy (homeworksucks):

Oh, you want positive .964785

OpenStudy (anonymous):

where do i take it from there?

OpenStudy (homeworksucks):

Yup, now in what quadrants are cosine negative?, since we started out with a negative secant

OpenStudy (anonymous):

second adn third

OpenStudy (homeworksucks):

Yea, so for the second quadrant, the real angle is pi-your reference angle, in third its your reference angle+pi, if you're doing it in radians.

OpenStudy (anonymous):

ohh ok i got it now.. thank you so much!

OpenStudy (homeworksucks):

No problem!

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