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What is the simplified form of (posting problem shortly :D)
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\[\frac{ 1 }{ 8xy }\times \frac{ 4x^2 }{ 3y }\]
@phi
x/(6y)
y^2...
could you explain how? @nukka
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numerator=4x^2 denominator expands to 24xy^2 4/24=1/6 x^2/x=x 1/y^2=1/y^2 Multiply them together to get your answer
Thanks! Do you think you could help with another? (Similar to this one) @nukka
go for it
\[(\frac{ x }{4 } + \frac{ y }{ 3 })\div(\frac{ x }{ 3 } - \frac{ y }{ 4 })\] @nukka
(x/4+y/3)/(x/3−y/4) =(3x/12+4y/12)/(4x/12-3y/12) =(3x+4y)/(4x-3y)
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thank you sooo much!!
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