Question

d/dy sqrt( x+e^(4y) )

Answer 1

hi

Answer 2

hi :)

Answer 3

i got 1/2(x+e^(4y))*4e^(4y) is this correct?

Answer 4

This is a partial derivative with respect to y? Or just a normal derivative wrt y? :o

Answer 5

how will that be different if it's normal or not?

Answer 6

If it's a partial derivative, x is held constant.
If it's a normal derivative, we will be getting a dx/dy term (or x') at some point.

Answer 7

\[\Large \frac{\partial}{\partial y}\sqrt{x+e^{4y}} \quad=\quad \frac{1}{2\sqrt{x+e^{4y}}}(4e^{4y})\]

Answer 8

Looks like you've got the right idea, maybe you just made a typo?
I don't see the square root in your solution.

Answer 9

Just so there is no confusion, if it had been a normal derivative with respect to y, we would get:\[\Large \frac{d}{dy}\sqrt{x+e^{4y}} \quad=\quad \frac{1}{2\sqrt{x+e^{4y}}}\left(\frac{dx}{dy}+4e^{4y}\right)\]

Answer 10

oh so if it's partial then i should consider to take derivative only respect to Y

Answer 11

but if it's normal then i should consider for whole thing inside of ( )

Answer 12

ya :) in partial y... x=c.
in normal, x is a function, giving us those nasty derivative terms :3

Answer 13

err x is a variable, blah whatever.

Answer 14

i've been learning partial for weeks and getting confuse between normal and partial T.T

Answer 15

oh boy :x

Answer 16

getting used to do partial and forgetting normal..

Answer 17

Ya partials seem to make a little more sense XD lol

Answer 18

haha thank you so much for your help!