Question

Solve the given linear system
-2x+3y=8
3x+5y=-12

Answer 1

With a graphing calculator, substitution, elimination, or matrix.
Graphing calculator is always the easiest.

Answer 2

Put the equations in slope-intercept form and graph it on your calculator. Then find the intercept, you hit the second key and then trace, then hit 5. Click enter 3 times since your lines are linear, you do not need to worry about 2 intersections. Then your x and y value should show. Good luck my friend.

Answer 3

but we dont have graphing calculator

Answer 4

Here's an online graphing calculator,
https://sites.google.com/site/northwesternhighschoolptsa/free-online-graphing-calculator

Answer 5

It's free, and if your teacher doesn't let you use that then use the elimination method.

Answer 6

thanks.. does it provide solutions?

Answer 7

What?

Answer 8

Solve for y in your equations and then plug it in to the calculator.

Answer 9

I could get you started on the elimination method.

Answer 10

-2x+3y=8
3x+5y=-12

You want to cancel out one of the variables, -2x and 3x looks like the easiest to me.
Make sure one of them is negative and one of them is positive so you can cancel out both of them.
3{-2x+3y=8}
2{3x+5y=-12}
(Distribute 3 and 2 to everything, including that 8 and -12)
-6x-9y=-24
6x+10y=-24
(x cancels out, 6-6=0)
y=-48
Looks like you got an easy one.
Plug in -48 into any of that equations for y.
(I'm just going to use the first one.)
-2x+3(-48)=8
-2x-144=8
+144
-2x=152
x=-76

Answer:
x=-76
y=-48
Or, (-76,-48)

Answer 11

where did you get 3&2?

Answer 12

and how did you get the 48?
im really sorry if i dont get it much

Answer 13

i think i get it..

Answer 14

now the second one is x=-84

Answer 15

The 3 and 2 was something I had to come up on my own. You can multiply 3 and 2 to get a 6. Only one has to be a negative so when you add the equations together, a positive plus a negative will cancel out because they are the same number.

I got a -48 by adding -24 and -24