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find the slope of the tangent line to the polar curve r=1+cos(theta) at the point theta=pi/6
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well slope of the tangent line is the derivative, and the derivative of 1+cos(theta) is -sin(theta) and when theta= pi/6, on the unit circle, sin is at 1/2, with the negative out front, the answer would be -1/2 is that what you were looking to do?
hi! thanks for helping me out but thats the wrong answer according my online hw submitter. that's what i did originally too i took the derivative and plugged in pi/6 and its still wrong
hmmm. Have you tried using a graphing calculator?
yes and it gives me the same answer
oh i think i have to do dy/dx ?
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