How do I find the initial height of the ball if the equation is h=-16t^2+58t+3

Question

campbell_st · Answer

so the equation is for the height of a ball at some time t. 

initial means let t= 0

so substitute t = 0 and solve, that will be the initial height

anonymous · Answer

How would I figure out how many seconds the "baseball"is when it's 40ft above the ground? (what the scenario is about lol) thanks by the way!

campbell_st · Answer

ok... so let h(t) = 40 and then solve for t

you get 

$$40 = -16t^2 + 58t + 3$$

or

$$16t^2 - 58t + 37 = 0$$

use the general quadratic formula to find the time... there should be 2 answers

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hope this helps