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Use the substitution method to solve the following system of equations. 3x + 5y = 3 x + 2y = 0
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(1,3/5)
for the first one
These are my answer choices. (1, 1) (6, –3) (6, 1) (1, –3)
ya i just redid that lol
hold on
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(1,-3)
x + 2y = 0 x = -2y now sub -2y in for x in the other equation 3x + 5y = 3 3(-2y) + 5y = 3 -6y + 5y = 3 -y = 3 y = -3 x = -2y x = -2(-3) x = 6 x = -6, y = -3 or (6,-3)
oops...it is not-6, it is 6
dang i did something wrong then im sorry
if I had $1 for every mistake I made...I would be rich...lol
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Its okay I did it and I didn't get the same answer. Then I got the same answer as @texaschic101 .
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