Science question but completely math application

Question

amtran_bus · Answer

The spectrum line shows at 35 cm and the transmission diffraction grating is 95 cm from the light source spectrum tube.  If the distance between lines on the diffraction grating is 1700nm what is the wavelength of this yellow light in nm?

amtran_bus · Answer

Use n*wavelength=D*sin theta?

amtran_bus · Answer

How to apply it in that formula, solving for wavelength?

anonymous · Answer

wavelength=dsintheta/n

amtran_bus · Answer

Thanks!  So would it be 95*sin theta/35?
What would sine be?
@Nameless

anonymous · Answer

I dont now how to approach this problem, im sorry.

amtran_bus · Answer

Its ok, thanks for looking.

anonymous · Answer

so this light comes out of a tube.. a spectrum and defracts and you want to find the measurements of one of the sides of the triangle?

anonymous · Answer

maybe for theta you could use arcsin(wavelength/grating element (1/n))

amtran_bus · Answer

True.  But we have not even discussed that in class.  I am hesitant to try it.

anonymous · Answer

ok lol, ill stop trying to help with somehting I know nothing about :)