Question

Solve the equation. Check the solution.

Answer 1

D.2

Answer 2

sorry now does it make sense lol

Answer 3

yup ! looks last time u posted a diff q wid these options lol

Answer 4

lol yeah true i copied and pasted it but i forgot to copy the new question lol

Answer 5

\(\huge \frac{-4}{x+1} = \frac{-1}{x+1} \)

Answer 6

wat should be our first step ?

Answer 7

no the bottom on the right is x+5

Answer 8

see that, i have negative both sides. lets cancel them, as i hate negative numbers

Answer 9

was just checking u r alert or not lol ;)

Answer 10

lol yeah im alert trust me good test though

Answer 11

\(\huge \frac{-4}{x+1} = \frac{-1}{x+5} \)

Answer 12

like this right

Answer 13

lets multiply both sides by -1.
that gets rid of negatives

Answer 14

okay n yes its right

Answer 15

\(\huge \frac{-4}{x+1} = \frac{-1}{x+5} \)

multiply -1 both sides

\(\huge \frac{4}{x+1} = \frac{1}{x+5} \)

Answer 16

next, cross multiply
u knw how to cross myltiply right ? :)

Answer 17

4x5 and 1x1 right?

Answer 18

who ate x's lol

Answer 19

times lol

Answer 20

\(\huge \frac{-4}{x+1} = \frac{-1}{x+5} \)

multiply -1 both sides

\(\huge \frac{4}{x+1} = \frac{1}{x+5} \)

cross multiply

\(\large 4(x+5) = 1(x+1)\)

Answer 21

entire bottom thing (x+5) or (x+1) multiplies wid the cornery tops ok

Answer 22

next, distriibute and simplify a bit

Answer 23

4x+20=1x+2 right

Answer 24

\(1 \times 1 = 1\)

Answer 25

\(1 \times 1 \ne 2\)

Answer 26

yeah ur right sorry 1

Answer 27

ok

Answer 28

im sure u r checking my alerttness nw -.-

Answer 29

\(\huge \frac{-4}{x+1} = \frac{-1}{x+5} \)

multiply -1 both sides

\(\huge \frac{4}{x+1} = \frac{1}{x+5} \)

cross multiply

\(\large 4(x+5) = 1(x+1)\)


\(\large 4x+20 = x+1\)

Answer 30

next, subtract x both sides

Answer 31

yeah lol how would u do that?

Answer 32

\(\huge \frac{-4}{x+1} = \frac{-1}{x+5} \)

multiply -1 both sides

\(\huge \frac{4}{x+1} = \frac{1}{x+5} \)

cross multiply

\(\large 4(x+5) = 1(x+1)\)


\(\large 4x+20 = x+1\)

subtract x both sides
\(\large 4x+20 = x+1\)
-x -x

\(\large 3x+20 = 1\)

Answer 33

\(\huge \frac{-4}{x+1} = \frac{-1}{x+5} \)

multiply -1 both sides

\(\huge \frac{4}{x+1} = \frac{1}{x+5} \)

cross multiply

\(\large 4(x+5) = 1(x+1)\)


\(\large 4x+20 = x+1\)

subtract x both sides

\(\large 3x+20 = 1\)

subtract 20 both sides

\(\large 3x = -19\)

divide 3 both sides

\(\large x = -\frac{19}{3}\)

Answer 34

there is the complete solution. Enjoy..

Answer 35

that isnt an option

Answer 36

It's C. Your last choice.

Answer 37

^^ option C :) you sure need to take some rest before moving to next problems... :|