Question

Solve each radical equation. Check your solution.
Square root 5x^2-3x=2x

Answer 1

is it
\[\sqrt{5x ^{2} - 3x } = 2x \]
or
\[\sqrt{5x ^{2}} -3x = 2x\]
or
\[\sqrt{5}x ^{2} - 3x = 2x\]

I think it's the first one ?

Answer 2

How do you solve it and yes it is the first one and how do you solve it

Answer 3

\[\sqrt{5x^2-3x}=2x\]

Answer 4

Here how to do it:

Answer 5

First square root each side to remove the square root, which means you gonna have to use the square method on "2x" which equals "4x^2"