what is the quadratic formula
formula to solve quadatic equations \(ax^2+bc+c=0\) \(\huge x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\)
****\(ax^2+bx+c=0\)
yes,right but @gohangoku58 sorry,it would better if you say \(\sf \Large x _{1} \ and \ x _{2}\)
not just x
if he know that there must be 2 solutions then its understood
yes,right but we have two solution and x is single
Any ways there is no x1 and x2 everything x which has two sollutions
suit yourself with the nomenclature :) more important is the right side ....
Therefore it would be incorrect if we say x1 and x2 as they are two different things but in quadractics we only have to find 1 thing which is the variable "x"
yes x has to solution but look: x = (two solution) and x is single but in second side we have two! so ... ok nice :)
ok
To remember the quadratic formula use this bee story trick, this is what I used when I was learning:
negative bee = -b could not decided = + and - radical party = √ square bee = b^2 threw down 4 aces = -4ac 2am = 2a
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