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Mathematics 20 Online
OpenStudy (anonymous):

I have some dimes and nickels which is $0.65. if my dimes were nickels and my nickels were dimes, I would have $0.85 how many dimes and nickels do I have?

OpenStudy (anonymous):

long problem lol

OpenStudy (anonymous):

Hey i am Working that stuff out give me a min :D

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

??????????

OpenStudy (anonymous):

I don't get it

OpenStudy (anonymous):

I will try but its tough and a difficult nut to crack.

OpenStudy (anonymous):

yep im testing others on some questions soo yea (this is one of them)

OpenStudy (anonymous):

Consider a system of equations using \(n,d\) as variables.

OpenStudy (anonymous):

yes do that

OpenStudy (anonymous):

\[\begin{split} 5n&+10d&=65\\ 10n&+5d&=85 \end{split} \]

OpenStudy (anonymous):

yesss good now add them!!

OpenStudy (anonymous):

multiply the first equation by 2

OpenStudy (anonymous):

You can use elimination or substitution.

OpenStudy (anonymous):

ummm I would add them making 15n + 15d = 150

OpenStudy (anonymous):

No

OpenStudy (anonymous):

then divide the equaton by 15

OpenStudy (anonymous):

multiply the first equation by -2

OpenStudy (anonymous):

next divide the first equation by 5

OpenStudy (anonymous):

Add then both the equations and tell me

OpenStudy (anonymous):

then u find out that d = 3!!

OpenStudy (anonymous):

soo n = 7

OpenStudy (anonymous):

review the past to understand

OpenStudy (anonymous):

nice job @wio

OpenStudy (anonymous):

good more coming up MABYE!!

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