help..........
A man has two more nickels than dimes. He has $1.15 in all. How many coins of each kind does he have?

Which equation can be used to solve the problem?

5x + 10(x + 2) = 115
5(x + 2) + 10x = 115
x + x + 2 = 115

Question

help..........
A man has two more nickels than dimes. He has $1.15 in all. How many coins of each kind does he have?

Which equation can be used to solve the problem?


5x + 10(x + 2) = 115
5(x + 2) + 10x = 115
x + x + 2 = 115

austinl · Answer

Well, nickles appear to be the x value in this problem.
So,
it is x+how many more he has than dimes.

Which one appears to satisfy that?

anonymous · Answer

is it the first one......5x+10(x+2)=115

austinl · Answer

Ok... now that I look at this....
5 is the value for nickles
10 is the value for dimes

5x+10x=115

That means that they have equal values for each coin to add up to $1.15

But there are two more dimes than there are nickles, so,

5(x+2)+10x=115

anonymous · Answer

ok.. thankx