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HElp with writing an expression as a single logarithm
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\[\frac{ 5 }{ 6 }\log _{2}(x)+2/3\log _{2}(y)-1/2\log _{2}(x)-\log _{2}(y)\] my professor said you should on the second part change the -log_{2}(y) to +log_{2}(y) Is this correect?
Many people in my class thought itwouldbe wrong and just worked it out the other way. this is very confusing.
first, combine the similar terms we get : 5/6log_2 (x) + 2/3log_2 (y) − 1/2log_2 (x) − log_2 (y) = 5/6log_2 (x) − 1/2log_2 (x) + 2/3log_2 (y) - log_2 (y) = (5/6 - 1/2)log_2 (x) + (2/3 - 1)log_2 (y) = -1/3log_2 (x) - 1/3log_2 (y) then factor out and simplify = -1/3 {log_2 (x) + log_2 (y)} = -1/3 log_2 (xy) = log_2 (xy)^(-1/3) = log_2 1/(xy)^(1/3)
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