Question

given the function g(x)=-x^2-4x-3, find g(-1/3)

Answer 1

\[\huge \mathbb{\color{orange}{WELCOME ~TO~OPENSTUDY}}\]
What you do is plug in -1/3 so solve this:
\[\Large g(-\frac{1}{3})=-(\frac{1}{3})^2-4(-\frac{1}{3})-3\]

Answer 2

How can I solve it though?

Answer 3

By evaluating the numbers I provide.

Answer 4

Is there a way to get rid of the denominators to convert it into normal variables and get the right answer?