Question

Determine the P-value for the hypothesis test.

See attachment.

Answer 1

@amistre64 can u help with this?

Answer 2

if i can read it ...

Answer 3

the Pvalue, is the tail values when using one of the means as a reference point

Answer 4

ok?...

Answer 5

you should be able to find a zscore, and a right tail value using:\[Z=\frac{\mu_{f} -\mu_{sp}}{\frac{10.5}{\sqrt{25}}+\frac{13}{\sqrt{27}}}\]

Answer 6

I thought i was supposed to be using T not Z.

Answer 7

.... then use the T :) but it has something to do with that sort of setup i believe

Answer 8

i forget the "degree of freedom" associated with it to run a t

Answer 9

Cant u be awesome and just give me the answer?

Answer 10

of course not ... even if I knew the answer :/

Answer 11

lol then can't u figure it out? cause it don't help if u don't know the answer.

Answer 12

im sure i can figure it out ... just have to review some stuff in my textbook :)

Answer 13

this is the example i have for this. It's not very helpful tho.

Answer 14

its a little useful .....

Answer 15

lol not to me. They don't show how they got there answer.

Answer 16

a t formula for 2 means, from my book says
\[t=\frac{\bar x_1-\bar x_2}{\sqrt{\frac{s^2}{n_1}+\frac{s^2}{n_2}}}\]
\[t=\frac{72.6-67.1}{\sqrt{\frac{10.5^2}{25}+\frac{13^2}{27}}}\]

Answer 17

im getting t = 1.68

have you already got a t score for this?

Answer 18

using "technology"; my ti83 has a tcdf function that takes the parameters: low, high, df

Answer 19

i'm trying to work this hang on.

Answer 20

low is our t score
high is some arbitrary large value in this case
and the df is .. 24

Answer 21

i got 1.68 as the answer to.

Answer 22

im assuming you have a few freebies; see if .053 gets accepted as the Pvalue

Answer 23

YAY THAT WAS RIGHT!!!!

Answer 24

whew .... i was worried if that t score was done right lol

Answer 25

how did u get that?

Answer 26

the formula in my book says; subtract the means, and divide by that sqrt stuff. so thats what I did

Answer 27

that t score i used in the tcdf function; using 9999 as some large number to find the area in the right tail with. the lowest df was 25-1

Answer 28

when i hit enter, it said .052964... lol

Answer 29

english!!! lol i need to write it in my notes.

Answer 30

subtract one mean from the other; divide it by ..\[\sqrt{\frac{(s_1)^2}{n_1}+\frac{(s_2)^2}{n_2}}\]
and that gets you a t score

Answer 31

yah i got that

Answer 32

then i found a tcdf function on my calculator; do you ahve a calculator to use?

Answer 33

I have this one

Answer 34

hmm, i got no idea where, or if, that has a tcdf function

Answer 35

yah probably not. one sec i'll look

Answer 36

i'm not seeing it

Answer 37

well i'll skip it for now and figure it out later.

Answer 38

hit shift, 1, stat what do you see for a menu?

Answer 39

nothing

Answer 40

i'll work on that later when i find the manual thing

Answer 41

thx 4 the help tho!!

Answer 42

well, the results are the output from the tcdf function, so if there is no way to get to it ... the rest is just up in the air

Answer 43

maybe mode, 3

Answer 44

i know how to find t now so i can use a P-value calculator online if i need to.

Answer 45

yeah, just make sure you get the area under the proper tail :)

Answer 46

im off to pick up the kids ... good luck