Question

Please help me out in this question ill give a GOLD MEDAL!!! if u help me

Answer 1

What is the question?

Answer 2

Heres the question I might take a bit long

Answer 3

How do I graph and shade the region of this equations x + 2y < or equal to 6
2x - y < or equal to 7
x > or equal to -2, y > or equal to -3
F (x, y) = x + y
Please show me how...

Answer 4

Equation:
\[x+2y \le 6\]
1. Solve for a variable/ Get into slop-intercept form(y=mx+b)
2. Graph

Advice:
1. if the sign is less than:
shade below w/ a dashed line
2. if the sign is greater than:
shade above w/ a dashed line
3. if the sign is less than or equal to:
solid line and shaded below
4. if the sign is greater than or equal to:
solid line and shaded above

Answer 5

Can u please show me I have it already I just want tk c if im right?

Answer 6

@texaschic101 pleade help me

Answer 7

x + 2y <= 6
2y <= -x + 6
y <= -1/2x + 3 -- -1/2 is your slope and 3 is your y intercept.

your x intercept can be found by subbing in 0 for y
x + 2y < = 6
x + 0 <= 6
x <= 6......your x intercept is 6

so plot your intercept points : x int = (6,0) and y int = (0,3). Now connect the points with a solid line.

you have an equal sign included, therefore you line will be solid. You have a greater then or equal sign, so your shading will include the line and everything above it.