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Use mathematical induction to prove that the statement is true for every positive integer n. 2 is a factor of n2 - n + 2
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Start by proving the base case: \(n=1\)
i dont know how too.
\[ (1)^2-(1)+2 \]
Show that it is a factor of \(2\)
of so'd it be (2)^2 - (2) + 2 ?
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4 - 2 +2 = 4?
No, show that when \(n=1\) it's a factor of \(2\).
how do i that?
We are beyond high school now. We know how to substitute values into variables.
so it'd be 2 - 1 + 2? = 3
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Okay so we have:\[ n^2 - n + 2 \]What does it equal when \(n=1\)?
1^2 - 1 + 2 = 2 - 1 +2 = 3?
\(1^2\neq 2\)
okay so the statement isnt true?
The problem is that you aren't doing the exponent correctly.\[ 1^2=1\times 1=1 \]
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