Question

PLEASE HELPPP!!!!!!


....
solve 5x^3-6x^2-4x-8=0

Answer 1

like are you supposed to use factoring to do this

Answer 2

a. 1/5+4/5i, -2/5+6/5i, 4
b. -2/5+4/5i, -2/5-4/5, 2
c. -2/6+4/5i,-4
d.1/5+2/5i,-3/5+-3/5i, 3

Answer 3

You could factor the equation and obtain
(x-2)*(5*x^2+4*x+4). This way you would see
one solution in the first set of brackets.
If x=2 then the first term becomes zero and hence
the total expression becomes zero. This means, you
have a solution.
The other two solutions are complex

Answer 4

you can rewrite it as