Mathematics
7 Online
OpenStudy (anonymous):
Hey guys. Will you help me find the solution to this function?
g(x)=4x2+8x+2
Fan/medal for help and answer. :)
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OpenStudy (anonymous):
I can help but no medal please
OpenStudy (anonymous):
Okay. :)
OpenStudy (anonymous):
but then what will you give?
OpenStudy (anonymous):
I'll fan you?
OpenStudy (anonymous):
Or I can try to help on anything you may need help with. I'm good at English and Chemistry.
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OpenStudy (anonymous):
K sounds good
g(x)=0
OpenStudy (anonymous):
How'd you get that?
OpenStudy (anonymous):
4x2+8x+2 = 0 so 4x^2+4x+2x+2=0
x = -1 or x =-1/2
OpenStudy (anonymous):
wait I made a mistake
OpenStudy (***[isuru]***):
hate to say this @thisSucks ,,, but u r wrong!!!
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OpenStudy (***[isuru]***):
u can't factorize that one ....
OpenStudy (anonymous):
you could also use the quadratic formula to solve this
OpenStudy (***[isuru]***):
u have to use either completing square or the formula
OpenStudy (***[isuru]***):
but before that ....
is g(x) = 0 ?
OpenStudy (anonymous):
Yeah SURU is right
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OpenStudy (anonymous):
you have to use the formula
OpenStudy (***[isuru]***):
u can't solve g(x) , if g(x) is just an expression...
OpenStudy (anonymous):
Completing the square is actually the name of the lesson. All I know is that it will have two irriational solutions due to the rules of discrimnants.
OpenStudy (***[isuru]***):
so.... go on with completing square....
OpenStudy (anonymous):
Yeah so you can apply the formula there. Sorry I made the mistake :(
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OpenStudy (***[isuru]***):
let's assume that g(x) = 0 ... Otherwise u won't get any answers...
OpenStudy (anonymous):
(2x+2)^2 -2 =0
OpenStudy (***[isuru]***):
first step....
\[g(x) =4x ^{2} +8x +2\]
OpenStudy (***[isuru]***):
take 4 as common factor... out of the expression
OpenStudy (anonymous):
Okay. But what happens with the two?
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OpenStudy (***[isuru]***):
\[g(x) = 4( x ^{2} + 2x + \frac{ 1 }{ 2 })\]
OpenStudy (***[isuru]***):
now... wt is the next step... in ur lesson ?
OpenStudy (***[isuru]***):
divide the coefficient of x by 2 and write x and that value of the coefficient as a complete square...
OpenStudy (***[isuru]***):
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