Question

Solutions to: h(x)=6x2+4x+3

Fan/medal for help. :)

Answer 1

6x^2**

Answer 2

what do u want?

Answer 3

To find the solutions to the function.

Answer 4

of the function*

Answer 5

mean max or min?

Answer 6

What?

Answer 7

do u mean maximum value of it?

Answer 8

No. There are two complex solutions to this, and I want to find out what they are.

Answer 9

ok

\[\frac{ -4\pm i2\sqrt{14} }{ 12 }\]

Answer 10

How'd you get that?

Answer 11

\[\Delta= b ^{2}-4ac\]
\[x=\frac{ -b \pm \sqrt{\Delta} }{ 2a }\]

Answer 12

The solutions for the quadratic equation \[ax ^{2} + bx + c = 0 \] is:
\[\frac{ -b \pm \sqrt{b ^{2} - 4ac} }{ 2a }\]

Answer 13

\[ax ^{2} + bx + c\]

Answer 14

I know that but that's not what we're learning right now. The lesson is completing the square.

Answer 15

u mean complex numbers?

Answer 16

No, the lesson is completing the square. But, in the complex numbers lesson, they said that if the discriminant is negative, there will be two complex solutions to the function.

Answer 17

The discriminant for h(x) is -56.

Answer 18

ya
right

Answer 19

what is wrong with it?

Answer 20

I need to know how you got your answer. I don't understand HOW to find the solutions. If you just tell me, I'm not learning anything.

Answer 21

\[\sqrt{-56} = i \sqrt{4x14} = 2i \sqrt{14}\]
where i is defined as \[\sqrt{-1}\]

Answer 22

ya
right

Answer 23

\[\sqrt{-56}=\sqrt{-4\times14}=i2\times \sqrt{14}\]

Answer 24

4 times 14 not the letter "x" above

Answer 25

Okay, then what?

Answer 26

Waaaaaaaait. Where'd you get the 14?

Answer 27

56 = 4 * 14

Answer 28

Ohhhhhhhhhh. Okay. But what happens to the rest of the function-?

Answer 29

u know
\[\sqrt{-1}= i\]

Answer 30

Yes...

Answer 31

so
\[\sqrt{-56}= \sqrt{-1\times4\times14}= i2\times \sqrt{14}\]

Answer 32

But where's the 12 come from in your solution? And there is supposed to be two solutions, not just one.

Answer 33

a=6
2a=2*6 = 12

Answer 34

there is two solutions
mention the signs in the formula

Answer 35

So the other solution is negative rather than positive?

Answer 36

ya

Answer 37

What does it look like? I promise it's my last question.

Answer 38

ok


\[x1 = \frac{ -4 + i2\sqrt{14} }{ 12}\]

\[x2 =\frac{ -4 - i2\sqrt{14} }{ 12 }\]

Answer 39

got??

Answer 40

Yup. Thank you. :)

Answer 41

well