What is the equation of the line in slope-intercept form that passes through the points (6,7) and (2,5)?

Question

anonymous · Answer

1. calculate for the slope: $$slope(m)=\frac{ y _{2} -y _{1}}{ x _{1}-x _{2} }$$
2. using one of the points (x1, y1 and the slope (m), find the equation of the line by plugging them into $$y-y _{1}=m(x-x _{1})$$ and simplify it.

anonymous · Answer

Thanks!

anonymous · Answer

np:)

calculusxy · Answer

Explaining this method is kind of hard, but I will try to explain it to you the best as I can.

The method that I personally use is rise/run. What I do in this is think about how I can connect the point on the y axis to the x axis. First, I count how many steps up/down do I have to do get to the x point using the vertical axis. So in this case you have to go down 4 steps meaning -4 as the rise. To do the run, I count how many steps I have to count to get to the x point. In this case I have to go right in two counts. 

So rise/run=-4/2 or also -2