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5√(x-6) = -20
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The answer is no solution. Why is it no solution? How would I go about this?
for the simple logical reason, the square root does not yield a negative number..... to actually prove that, first square both sides, find the value of x and then check whether it satisfies the original equation
So it is a rule?
rule or not,here you can prove that by getting the value of x and verifying..
So, I would divide by 5, square it, and then solve for x?
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when you square it, you are attaching an extraneous solution
and yes, do that
\[\sqrt{x-6} = -4\] \[x-6 = 4^{2}\] \[x-6 = 16\] x = 22
good!
Oh! I get it now! If I plug in this value for the original equation, it won't work.
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exactly! :)
Thanks!
welcome ^_^
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