Question

f(x) = 2xsqrtx+4/x+1, find g(-3)

Answer 1

If g was not defined, g(-3) is an undefined value.

Answer 2

\[f(x)=\frac{2x\sqrt{x+4}}{x+1}\]
\[f(-3)=\frac{2\times (-3)\sqrt{-3+4}}{-3+1}\] is a start

Answer 3

f(-3) = -6 sqrt7/-2?

Answer 4

not quite
inside the radical is \(-3+4=1\) not \(7\)

Answer 5

and so the radical part becomes \(\sqrt{-3+4}=\sqrt 1=1\)

Answer 6

I'm sorry. I had 3 + 4. I mistyped

Answer 7

Thanks. You're a jewel

Answer 8

yw (blush)