Question

Which of the equations is satisfied by the five pairs of numbers listed in the table attached inside?

a. y=x^3+3

b. y=3x+3

c. y=-3x+6

d. y=x^2+6

e. y=x^2-7

Answer 1

TABLE!

Answer 2

Can you please explain this step by step to me? I don't get it at all :(

thank you!!

Answer 3

okay. am i supposed to just plug in and see if it applies?

Answer 4

what do you mean by that?

Answer 5

ok, lets plug in the values of x and y
each equation

Answer 6

put x=1 in y=x^3+3
do u get y=6 ?

Answer 7

okay... so for equation a, i get this?

y=-2^3+3

=-8+3

= -5
?

Answer 8

Plug and check

Answer 9

y=x

Answer 10

oh yeah for x=1, i got 6

Answer 11

so u got y=-5
but you wanted y=-3 right ?

so first option is not correct

Answer 12

got this ?
try it for y= 3x+3 now..

Answer 13

first ones wrong

Answer 14

okay so i get this?

y=3(-2)+3

=-6+3

= -3

so it works for (-2, -3) right?

Answer 15

You do have to plug in all values for x and see if the y value checks out in each of the equations.
My suggestion is to start with x value of 0. Plug that in all equations first.
That is a very easy point to check, and it will eliminate several equations right away.

Answer 16

yes, it works for -2,-3
now check other points, if it works for all, thats your answer :)

Answer 17

dont look at my comments :X

Answer 18

i won't :)

Answer 19

deleted it haha

Answer 20

do what hartnn said, plug in the numbers in the variables and see if y = x

Answer 21

so for 0, here's what i got @mathstudent55:

a: y=0^3+3 = 3 so yes

b: y=3(0)+3= 3 so yes

c: y= -3(0)+6=6 so no

d: y=0^2+6=6 so no

e: y=0^2-7= -7 so no

@hartnn, like this?

y=3(0)+3=3 so yes

y=3(1)+3= 6 so yes

y=3(2)+3=9 so yes

y= 3(4)+3= 12+3 = 15 so yes

so the answer is B??

Answer 22

yes

Answer 23

:)

Answer 24

good work @iheartfood :)

Answer 25

yay!! thank youu :)

Answer 26

welcome ^_^

Answer 27

By using x = 0 in all equations, only the first two remain.
Then by using x = 1, only one works.

Answer 28

ahh i see.. thanks guys!!! :)